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the equation for the least - squares regression line is (y = 116.4169-1…

Question

the equation for the least - squares regression line is (y = 116.4169-1.3392x).
part 1/4
part 2 of 4
(b) predict the july temperature for a city whose january temperature is 32°f. round the answer to one decimal place as needed.
the july temperature is predicted to be (square)°f.

Explanation:

Step1: Identify the regression - line equation

The regression - line equation is $y = 116.469-1.3392x$, where $y$ is the July temperature and $x$ is the January temperature.

Step2: Substitute the given value of $x$

We are given $x = 32$. Substitute $x = 32$ into the equation: $y=116.469 - 1.3392\times32$.

Step3: Calculate the value of $y$

First, calculate $1.3392\times32 = 42.8544$. Then, $y=116.469-42.8544 = 73.6146$.

Step4: Round the result

Rounding $73.6146$ to one decimal place, we get $y\approx73.6$.

Answer:

$73.6$