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Question
does the equation x = x + 3 have one solution, no solutions, or infinitely many solutions? subtract x from both sides of the equation and rewrite the remaining values. x = x + 3 -x -x \square = \square
Step1: Subtract $x$ from left side
$x - x = 0$
Step2: Subtract $x$ from right side
$x + 3 - x = 3$
Step3: Analyze resulting equation
$0 = 3$ is a false statement, so there are no values of $x$ that satisfy the original equation.
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The filled blanks are $0$ and $3$, and the equation has no solutions.