Question

for the equation shown below, the slope =
and the y-intercept is the
point ( , ).
$y + 32 = \frac{9}{5}x$
question 4 3 pts
for the equation shown below, the slope =
and the y-intercept is the
point ( , ).
$y + 12 = -11x + 15$

Explanation:

Step1: Rearrange to slope-intercept form

$y + 32 = \frac{9}{5}x$
$y = \frac{9}{5}x - 32$

Step2: Identify slope and y-intercept

Slope is the coefficient of $x$; y-intercept occurs at $x=0$.

Step3: Rearrange second equation to slope-intercept form

$y + 12 = -11x + 15$
$y = -11x + 15 - 12$
$y = -11x + 3$

Step4: Identify slope and y-intercept for second equation

Slope is the coefficient of $x$; y-intercept occurs at $x=0$.

Answer:

First equation:
Slope = $\frac{9}{5}$, y-intercept point = $(0, -32)$

Second equation:
Slope = $-11$, y-intercept point = $(0, 3)$