QUESTION IMAGE
Question
for #6 - 9, evaluate each of the following if x = 4 and y = 3.
- $\frac{x - y}{x - y}$
- $\frac{x + y}{y + x}$
- $\frac{x - y}{y - x}$
- $\frac{x - y}{y + x}$
- if a, b, and c are all positive integers, which graph could represent the sketch of the graph of $p(x)=-a(x + b)(x^{2}-2cx + c^{2})$?
- which of the following functions best models the graph pictured below?
- $f(x)=(x + 1)^{2}(x - 2)$
- $f(x)=(x - 1)^{2}(x + 2)$
- $f(x)=(x + 1)(x - 2)^{2}$
- $f(x)=(x - 1)(x + 2)^{2}$
Step1: Evaluate problem 6
Substitute \(x = 4\) and \(y=3\) into \(\frac{x + y}{x - y}\).
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Step2: Evaluate problem 7
Substitute \(x = 4\) and \(y = 3\) into \(\frac{x + y}{y + x}\). Since \(x + y=y + x\), \(\frac{4+3}{3 + 4}=\frac{7}{7}=1\).
Step3: Evaluate problem 8
Substitute \(x = 4\) and \(y = 3\) into \(\frac{x - y}{y - x}\). We have \(x - y=4 - 3 = 1\) and \(y - x=3 - 4=-1\), so \(\frac{4 - 3}{3 - 4}=\frac{1}{-1}=-1\).
Step4: Evaluate problem 9
Substitute \(x = 4\) and \(y = 3\) into \(\frac{x - y}{y + x}\). \(x - y=4 - 3 = 1\) and \(y + x=3 + 4 = 7\), so \(\frac{4 - 3}{3+4}=\frac{1}{7}\).
Step5: Solve problem 10
First, factor \(x^{2}-2cx + c^{2}=(x - c)^{2}\). Then \(p(x)=-a(x + b)(x - c)^{2}\). The roots of the polynomial are \(x=-b\) and \(x = c\) (with multiplicity 2). Since \(a>0\), the leading - coefficient of \(p(x)\) is negative. As \(x\to\pm\infty\), \(y\to-\infty\). The graph touches the \(x\) - axis at \(x = c\) (because of the multiplicity 2) and crosses the \(x\) - axis at \(x=-b\). The correct graph is (1).
Step6: Solve problem 11
The roots of the polynomial function can be found by setting \(y = 0\).
For \(f(x)=(x + 1)^{2}(x - 2)\), the roots are \(x=-1\) (with multiplicity 2) and \(x = 2\). When \(x=-1\), the graph touches the \(x\) - axis (due to multiplicity 2), and when \(x = 2\), the graph crosses the \(x\) - axis. The function \(f(x)=(x + 1)^{2}(x - 2)\) best models the given graph.
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- 7
- 1
- -1
- \(\frac{1}{7}\)
- (1)
- 1) \(f(x)=(x + 1)^{2}(x - 2)\)