Question

evaluate the following functions.
you get unlimited reattempts.
$f(x) = -4x^2 - 4$
$g(x) = 13x - 9$
find $f(-7) + g(-7)$

Explanation:

Step1: Calculate \( f(-7) \)

Substitute \( x = -7 \) into \( f(x) = -4x^2 - 4 \).
\( f(-7) = -4\times(-7)^2 - 4 \)
First, calculate \( (-7)^2 = 49 \).
Then, \( -4\times49 = -196 \).
So, \( f(-7) = -196 - 4 = -200 \).

Step2: Calculate \( g(-7) \)

Substitute \( x = -7 \) into \( g(x) = 13x - 9 \).
\( g(-7) = 13\times(-7) - 9 \)
Calculate \( 13\times(-7) = -91 \).
Then, \( g(-7) = -91 - 9 = -100 \).

Step3: Calculate \( f(-7) + g(-7) \)

Add the results from Step1 and Step2.
\( f(-7) + g(-7) = -200 + (-100) = -300 \).

Answer:

\(-300\)