Question

evaluate the following limit:
\lim_{x \to 5} \frac{x - 3}{x^2 - 9}
\bigcirc 1/8
\bigcirc none of the other answers is correct.
\bigcirc indeterminate
\bigcirc 0
\bigcirc 3/4

Explanation:

Step1: Substitute $x=5$ into numerator

$5 - 3 = 2$

Step2: Substitute $x=5$ into denominator

$5^2 - 9 = 25 - 9 = 16$

Step3: Compute the fraction

$\frac{2}{16} = \frac{1}{8}$

Answer:

1/8