Question

example 2
a soccer team finished their season in which they won 18 times, lost 4 times, and tied 3 times. what is the probability that they win a game? write this as a percent?
check for understanding
a soccer team finished their season in which they won 18 times, lost 4 times, and tied 3 times. what is the probability that they didnt lose a game?

Explanation:

Step1: Calculate total number of games

The total number of games is the sum of wins, losses and ties. So, $18 + 4+3=25$ games.

Step2: Calculate number of non - loss games

Non - loss games are wins and ties. So, $18 + 3=21$ non - loss games.

Step3: Calculate probability of non - loss

The probability $P$ of an event is the number of favorable outcomes divided by the total number of outcomes. So, $P=\frac{21}{25}$.

Step4: Convert to percentage

To convert the fraction to a percentage, we multiply by 100. So, $\frac{21}{25}\times100 = 84\%$.

Answer:

$84\%$