exercise 3 (answers on page 41)
simplify the following fractions. reduce if possible.
1) $\frac{6}{5}$=
2) $\frac{5}{4}$=
3) $\frac{7}{3}$=
4) $\frac{10}{6}$=
5) $\frac{4}{2}$=
6) $\frac{6}{4}$=
7) $\frac{15}{3}$=
8) $\frac{20}{12}$=
9) $\frac{19}{4}$=
10) $\frac{23}{5}$=
11) $\frac{18}{3}$=
12) $\frac{17}{5}$=
13) $\frac{37}{9}$=
14) $\frac{28}{8}$=
15) $\frac{47}{9}$=
16) $\frac{106}{4}$=
17) $\frac{17}{2}$=
18) $\frac{140}{20}$=
19) $\frac{162}{10}$=
20) $\frac{38}{5}$=
21) $\frac{52}{3}$=

Question

Accepted Answer

# Explanation:
## Step1: Simplify or convert to mixed number
1) $\frac{6}{5}$ is improper; divide 6 by 5: $6=5	imes1+1$, so $1\frac{1}{5}$
2) $\frac{5}{4}$ is improper; divide 5 by 4: $5=4	imes1+1$, so $1\frac{1}{4}$
3) $\frac{7}{3}$ is improper; divide 7 by 3: $7=3	imes2+1$, so $2\frac{1}{3}$
4) $\frac{10}{6}$: GCD of 10&6=2, $\frac{10\div2}{6\div2}=\frac{5}{3}=1\frac{2}{3}$
5) $\frac{4}{2}$: 4÷2=2, so 2
6) $\frac{6}{4}$: GCD of 6&4=2, $\frac{6\div2}{4\div2}=\frac{3}{2}=1\frac{1}{2}$
7) $\frac{15}{3}$: 15÷3=5, so 5
8) $\frac{20}{12}$: GCD of 20&12=4, $\frac{20\div4}{12\div4}=\frac{5}{3}=1\frac{2}{3}$
9) $\frac{19}{4}$ is improper; divide 19 by 4: $19=4	imes4+3$, so $4\frac{3}{4}$
10) $\frac{23}{5}$ is improper; divide 23 by 5: $23=5	imes4+3$, so $4\frac{3}{5}$
11) $\frac{18}{3}$: 18÷3=6, so 6
12) $\frac{17}{5}$ is improper; divide 17 by 5: $17=5	imes3+2$, so $3\frac{2}{5}$
13) $\frac{37}{9}$ is improper; divide 37 by 9: $37=9	imes4+1$, so $4\frac{1}{9}$
14) $\frac{28}{8}$: GCD of 28&8=4, $\frac{28\div4}{8\div4}=\frac{7}{2}=3\frac{1}{2}$
15) $\frac{47}{9}$ is improper; divide 47 by 9: $47=9	imes5+2$, so $5\frac{2}{9}$
16) $\frac{106}{4}$: GCD of 106&4=2, $\frac{106\div2}{4\div2}=\frac{53}{2}=26\frac{1}{2}$
17) $\frac{17}{2}$ is improper; divide 17 by 2: $17=2	imes8+1$, so $8\frac{1}{2}$
18) $\frac{140}{20}$: 140÷20=7, so 7
19) $\frac{162}{10}$: GCD of 162&10=2, $\frac{162\div2}{10\div2}=\frac{81}{5}=16\frac{1}{5}$
20) $\frac{38}{5}$ is improper; divide 38 by 5: $38=5	imes7+3$, so $7\frac{3}{5}$
21) $\frac{52}{3}$ is improper; divide 52 by 3: $52=3	imes17+1$, so $17\frac{1}{3}$

# Answer:
1) $1\frac{1}{5}$
2) $1\frac{1}{4}$
3) $2\frac{1}{3}$
4) $1\frac{2}{3}$
5) $2$
6) $1\frac{1}{2}$
7) $5$
8) $1\frac{2}{3}$
9) $4\frac{3}{4}$
10) $4\frac{3}{5}$
11) $6$
12) $3\frac{2}{5}$
13) $4\frac{1}{9}$
14) $3\frac{1}{2}$
15) $5\frac{2}{9}$
16) $26\frac{1}{2}$
17) $8\frac{1}{2}$
18) $7$
19) $16\frac{1}{5}$
20) $7\frac{3}{5}$
21) $17\frac{1}{3}$

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Question

Explanation:

Step1: Simplify or convert to mixed number

Answer: