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an experiment was conducted to measure the effectiveness of various fee…

Question

an experiment was conducted to measure the effectiveness of various feed supplements on the growth of chickens. a five - number summary of the weights of the chicks in grams six weeks after hatching follows. source: anonymous (1948) biometrika, 35, 214. min = 119 q1 = 190 median = 257 q3 = 312 max = 426 1. about percent of the chicks weigh more than 190. 2. about percent of the chicks weigh more than 257. 3. about percent of the chicks weigh more than 312. 4. about percent of the chicks weigh between 190 and 312.

Explanation:

Step1: Recall quartile properties

In a data - set, Q1 is the first quartile (25th percentile), the median is the second quartile (50th percentile), and Q3 is the third quartile (75th percentile).

Step2: Calculate percentage for value 190

Since Q1 = 190, 25% of the data is less than or equal to 190. So the percentage of data greater than 190 is $100 - 25=75$.

Step3: Calculate percentage for value 257

Since the median = 257, 50% of the data is less than or equal to 257. So the percentage of data greater than 257 is $100 - 50 = 50$.

Step4: Calculate percentage for value 312

Since Q3 = 312, 75% of the data is less than or equal to 312. So the percentage of data greater than 312 is $100 - 75=25$.

Step5: Calculate percentage between 190 and 312

The percentage of data between Q1 (190) and Q3 (312) is $75 - 25 = 50$.

Answer:

  1. 75
  2. 50
  3. 25
  4. 50