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Question
express in simplest radical form. \\(\sqrt{2}\sqrt{6}\\) answer attempt 1 out of 2 submit answer
Step1: Use property of radicals $\sqrt{a}\sqrt{b}=\sqrt{ab}$
$\sqrt{2}\sqrt{6}=\sqrt{2\times6}$
Step2: Simplify the product inside the radical
$2\times6 = 12$, so we have $\sqrt{12}$
Step3: Factor 12 into perfect square and other factor
$12 = 4\times3$, so $\sqrt{12}=\sqrt{4\times3}$
Step4: Use property $\sqrt{ab}=\sqrt{a}\sqrt{b}$ again
$\sqrt{4\times3}=\sqrt{4}\sqrt{3}$
Step5: Simplify $\sqrt{4}$
$\sqrt{4} = 2$, so we get $2\sqrt{3}$
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$2\sqrt{3}$