Question

factor completely
$v^2 + 11v + 28$
$(v + 7)(v + 4)$
$(v - 7)(v + 4)$
$(v + 6)(v + 3)$
$(v + 7)(v -$

Explanation:

Step1: Identify $a,b,c$ for $ax^2+bx+c$

For $v^2 + 11v + 28$, $a=1$, $b=11$, $c=28$

Step2: Find pair summing to $b$, product $c$

Find two numbers: $7+4=11$, $7\times4=28$

Step3: Write factored form

Use the pair to factor: $(v+7)(v+4)$

Answer:

A. $(v + 7)(v + 4)$