Question

factor completely.
16y² - 4

Explanation:

Step1: Factor out GCF

$16y^2 - 4 = 4(4y^2 - 1)$

Step2: Apply difference of squares

$4y^2 - 1 = (2y)^2 - 1^2 = (2y-1)(2y+1)$

Step3: Combine factors

$4(2y-1)(2y+1)$

Answer:

$4(2y - 1)(2y + 1)$