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factor completely. $q^2 - 36$

Question

factor completely.
$q^2 - 36$

Explanation:

Step1: Recognize difference of squares

$q^2 - 36 = q^2 - 6^2$

Step2: Apply difference of squares formula

Recall $a^2 - b^2 = (a-b)(a+b)$, so substitute $a=q, b=6$:
$(q-6)(q+6)$

Answer:

$(q-6)(q+6)$