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factor completely. $-5v^2 + 17v - 6$

Question

factor completely.
$-5v^2 + 17v - 6$

Explanation:

Step1: Factor out -1

$-(5v^2 - 17v + 6)$

Step2: Split middle term

Find two numbers: product $5\times6=30$, sum $-17$. The numbers are $-15$ and $-2$.
$-(5v^2 - 15v - 2v + 6)$

Step3: Group and factor pairs

$-[5v(v - 3) - 2(v - 3)]$

Step4: Factor out common binomial

$-[(5v - 2)(v - 3)]$

Answer:

$-(5v - 2)(v - 3)$ or $(-5v + 2)(v - 3)$ or $(5v - 2)(-v + 3)$