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Question
factor to find all x-intercepts of the function.
$f(x) = x^3 - 5x$
answer attempt 1 out of 2
additional solution no solution
$x = $
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Step1: Factor out the common term
We can factor out an \(x\) from the function \(f(x)=x^{3}-5x\). So we get \(f(x)=x(x^{2} - 5)\).
Step2: Set each factor equal to zero
To find the \(x\)-intercepts, we set \(f(x) = 0\). This gives us two equations:
- \(x=0\)
- \(x^{2}-5 = 0\)
For the second equation \(x^{2}-5=0\), we can solve for \(x\) by adding 5 to both sides and then taking the square root. So \(x^{2}=5\), which gives \(x=\pm\sqrt{5}\)
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\(x = 0\), \(x=\sqrt{5}\), \(x = -\sqrt{5}\)