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Question
factor $x^3 - 4x^2 + 7x - 28$ by grouping. what is the resulting expression?\\(\bigcirc\\ (x^2 - 4)(x + 7)\\)\\(\bigcirc\\ (x^2 + 4)(x - 7)\\)\\(\bigcirc\\ (x^2 - 7)(x + 4)\\)\\(\bigcirc\\ (x^2 + 7)(x - 4)\\)
Step1: Group terms into pairs
$x^3 - 4x^2 + 7x - 28 = (x^3 - 4x^2) + (7x - 28)$
Step2: Factor out GCF from each pair
$= x^2(x - 4) + 7(x - 4)$
Step3: Factor out common binomial
$= (x^2 + 7)(x - 4)$
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D. $(x^2 + 7)(x - 4)$