Question

factor $0.04x^{2}+0.28x + 0.49$ using the perfect square trinomial method (if applicable).
a. $(0.2x + 0.7)^{2}$
b. $(0.2x - 0.7)^{2}$
c. not a perfect square trinomial
d. $0.04(x^{2}+7x + 12.25)$

Explanation:

Step1: Identify square terms

First term: $0.04x^2=(0.2x)^2$, last term: $0.49=(0.7)^2$

Step2: Verify middle term

Check $2\times0.2x\times0.7=0.28x$, matches given middle term.

Step3: Write perfect square form

Since all conditions are met, $0.04x^2+0.28x+0.49=(0.2x+0.7)^2$

Answer:

a. $(0.2x + 0.7)^2$