Question

fernando built a rectangular garden with a perimeter of 64 meters. the length of the garden, y, is 4 meters more than three times the width, x. which system of equations can be used to find the length and width of the garden in meters?
○ 2x + 2y = 64
y = 3x + 4
○ x + y = 64
y = 4x + 3
○ 2x + 2y = 64
y = 4x + 3
○ x + y = 64
y = 3x + 4

Explanation:

Step1: Recall perimeter formula

The perimeter $P$ of a rectangle is $P = 2x+2y$, and given $P = 64$, so $2x + 2y=64$.

Step2: Translate length - width relationship

The length $y$ is 4 meters more than three times the width $x$, so $y = 3x+4$.

Answer:

$2x + 2y=64$, $y = 3x+4$ (corresponding to the first - option in the multiple - choice list)