Question

in the figure below, q lies between p and r. find the location of q so that pq is $\frac{3}{8}$ of pr.

Explanation:

Step1: Calculate length of PR

$PR=26 - 10=16$

Step2: Calculate length of PQ

$PQ=\frac{3}{8}\times PR=\frac{3}{8}\times16 = 6$

Step3: Find location of Q

Let the location of Q be $x$. Then $x-10 = PQ$. So $x=10 + 6=16$

Answer:

16