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Question
in the figure below, (mangle nkm = 26^{circ}), (overline{kl}) bisects (angle jkm), and (overline{kn}) bisects (angle lkm). find (mangle jkl).
Step1: Recall angle - bisector property
Since $\overline{KN}$ bisects $\angle LKM$, then $m\angle LKM = 2m\angle NKM$. Given $m\angle NKM=26^{\circ}$, so $m\angle LKM = 2\times26^{\circ}=52^{\circ}$.
Step2: Use angle - bisector property again
Since $\overline{KL}$ bisects $\angle JKM$, then $m\angle JKL=m\angle LKM$.
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$52$