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Question
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the system of linear equations is shown below:
$3x + y = 23$
$2x - 2y = 2$
the solution is $(x,y) = (\quad,\quad)$.
Step1: Eliminate one variable
Multiply first equation by 2:
$$6x + 2y = 46$$
Add to second equation:
$$(6x + 2y) + (2x - 2y) = 46 + 2$$
$$8x = 48$$
Step2: Solve for x
Isolate x by dividing by 8:
$$x = \frac{48}{8} = 6$$
Step3: Substitute x to find y
Plug $x=6$ into first equation:
$$3(6) + y = 23$$
$$18 + y = 23$$
$$y = 23 - 18 = 5$$
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$(6, 5)$