Question

fill in the table using this function rule.
( y = -2x + 4 )
table with columns x and y, rows with x values -4, -2, 0, 2 and empty y cells

Explanation:

Step1: Substitute \( x = -4 \) into \( y = -2x + 4 \)

\( y = -2\times(-4)+4 = 8 + 4 = 12 \)

Step2: Substitute \( x = -2 \) into \( y = -2x + 4 \)

\( y = -2\times(-2)+4 = 4 + 4 = 8 \)

Step3: Substitute \( x = 0 \) into \( y = -2x + 4 \)

\( y = -2\times0 + 4 = 0 + 4 = 4 \)

Step4: Substitute \( x = 2 \) into \( y = -2x + 4 \)

\( y = -2\times2 + 4 = -4 + 4 = 0 \)

Answer:

When \( x = -4 \), \( y = 12 \); when \( x = -2 \), \( y = 8 \); when \( x = 0 \), \( y = 4 \); when \( x = 2 \), \( y = 0 \). So the completed table (from top to bottom for \( y \)) is \( 12, 8, 4, 0 \).