find the absolute value. |1 - i|

Question

Accepted Answer

# Explanation:
## Step1: Recall the formula for the absolute value of a complex number $ z = a + bi $, which is $ |z|=\sqrt{a^{2}+b^{2}} $. For the complex number $ 1 - i $, we have $ a = 1 $ and $ b=- 1 $.
## Step2: Substitute $ a = 1 $ and $ b=-1 $ into the formula. So we calculate $ a^{2}+b^{2}=1^{2}+(-1)^{2} $. First, $ 1^{2}=1 $ and $ (-1)^{2}=1 $. Then $ 1 + 1=2 $.
# Answer:
$ \sqrt{2} $ (the value inside the square root is 2)

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Question

Explanation:

Step1: Recall the formula for the absolute value of a complex number \( z = a + bi \), which is \( |z|=\sqrt{a^{2}+b^{2}} \). For the complex number \( 1 - i \), we have \( a = 1 \) and \( b=- 1 \).

Step2: Substitute \( a = 1 \) and \( b=-1 \) into the formula. So we calculate \( a^{2}+b^{2}=1^{2}+(-1)^{2} \). First, \( 1^{2}=1 \) and \( (-1)^{2}=1 \). Then \( 1 + 1=2 \).

Answer: