QUESTION IMAGE
Question
find the approximate side lengths and the perimeter of triangle uvw. if necessary, round your answers to the nearest hundredth.
the approximate length of side uv is
the approximate length of side vw is
the approximate length of side wu is
the approximate perimeter of triangle uvw is
Step1: Identify coordinates
Let \(U(-1,3)\), \(V(4,3)\), \(W(4, - 3)\).
Step2: Use distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\) for side UV
For \(U(-1,3)\) and \(V(4,3)\), \(x_1=-1,y_1 = 3,x_2=4,y_2 = 3\). Then \(d_{UV}=\sqrt{(4-(-1))^2+(3 - 3)^2}=\sqrt{(4 + 1)^2+0^2}=\sqrt{25}=5\).
Step3: Use distance formula for side VW
For \(V(4,3)\) and \(W(4,-3)\), \(x_1 = 4,y_1=3,x_2 = 4,y_2=-3\). Then \(d_{VW}=\sqrt{(4 - 4)^2+(-3 - 3)^2}=\sqrt{0+(-6)^2}=\sqrt{36}=6\).
Step4: Use distance formula for side WU
For \(W(4,-3)\) and \(U(-1,3)\), \(x_1 = 4,y_1=-3,x_2=-1,y_2 = 3\). Then \(d_{WU}=\sqrt{(-1 - 4)^2+(3+3)^2}=\sqrt{(-5)^2+6^2}=\sqrt{25 + 36}=\sqrt{61}\approx 7.81\).
Step5: Calculate perimeter
Perimeter \(P=d_{UV}+d_{VW}+d_{WU}=5 + 6+7.81=18.81\).
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The approximate length of side UV is 5 units.
The approximate length of side VW is 6 units.
The approximate length of side WU is 7.81 units.
The approximate perimeter of triangle UVW is 18.81 units.