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find the area of rectangle bcef. round the area to the nearest whole nu…

Question

find the area of rectangle bcef. round the area to the nearest whole number, if necessary. a(-5, 4) b(0, 3) f(-2, 1) c(4, -1) e(2, -3) d(4, -5) the area is square units.

Explanation:

Step1: Find length of BC

Using distance formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ for points B(0, 3) and C(4, -1):
$BC = \sqrt{(4 - 0)^2 + (-1 - 3)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2}$

Step2: Find length of BF

Using distance formula for points B(0, 3) and F(-2, 1):
$BF = \sqrt{(-2 - 0)^2 + (1 - 3)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Step3: Calculate area of rectangle

Area of rectangle = length × width = $BC × BF = 4\sqrt{2} × 2\sqrt{2}$
Simplify: $4×2×\sqrt{2}×\sqrt{2} = 8×2 = 16$

Answer:

16