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find the area of the sector. complete each line of the solution by movi…

Question

find the area of the sector. complete each line of the solution by moving one answer to each box. $a=\frac{1}{2}(quad)^2(quad)$ $a = (quad)\text{ in.}^2$

Explanation:

Step1: Recall sector - area formula

The formula for the area of a sector of a circle is $A=\frac{1}{2}r^{2}\theta$, where $r$ is the radius of the circle and $\theta$ is the central - angle in radians. First, convert the angle from degrees to radians. We know that to convert degrees to radians, we use the conversion factor $\theta_{rad}=\theta_{deg}\times\frac{\pi}{180}$. Given $\theta_{deg} = 200^{\circ}$, then $\theta=200\times\frac{\pi}{180}=\frac{10\pi}{9}$ radians, and $r = 4$ inches.

Step2: Substitute values into the formula

Substitute $r = 4$ and $\theta=\frac{10\pi}{9}$ into the formula $A=\frac{1}{2}r^{2}\theta$. So $A=\frac{1}{2}(4)^{2}(\frac{10\pi}{9})$.

Step3: Calculate the area

First, $(4)^{2}=16$. Then $\frac{1}{2}\times16\times\frac{10\pi}{9}= \frac{8\times10\pi}{9}=\frac{80\pi}{9}\approx27.93$ square inches.

Answer:

$A=\frac{1}{2}(4)^{2}(\frac{10\pi}{9})$; $A=\frac{80\pi}{9}\text{ in}^2$