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3) find p(a u b). assume that events a and b are not mutually exclusive…

Question

  1. find p(a u b). assume that events a and b are not mutually exclusive events. hint: p(a u b) = p(a) + p(b) - p(a ∩ b).

p(a) = 0.64
p(b) = 0.57
p(a ∩ b) = 0.49

Explanation:

Step1: Substitute given values

Substitute $P(A)=0.64$, $P(B)=0.57$, and $P(A\cap B)=0.49$ into the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$.
$P(A\cup B)=0.64 + 0.57- 0.49$

Step2: Perform addition

First, add $0.64$ and $0.57$.
$0.64+0.57 = 1.21$
So, $P(A\cup B)=1.21 - 0.49$

Step3: Perform subtraction

Subtract $0.49$ from $1.21$.
$1.21-0.49=0.72$

Answer:

$0.72$