Question

find the axis of symmetry of the parabola $y = x^2 - 2x + 1$.\
\
a. $x = -1$\
\
b. $x = \frac{1}{4}$\
\
c. $x = 1$\
\
d. $x = 0$

Explanation:

Step1: Identify coefficients

For $y=ax^2+bx+c$, $a=1$, $b=-2$

Step2: Apply axis formula

Use $x=-\frac{b}{2a}$
$x=-\frac{-2}{2\times1}$

Step3: Simplify the expression

$x=\frac{2}{2}=1$

Answer:

C. $x = 1$