Question

find the distance between the points (15.3, 6) and (3, -14). round decimals to the nearest tenth. units

Explanation:

Step1: Identify distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 15.3$, $y_1=6$, $x_2 = 3$, $y_2=-14$.

Step2: Calculate differences

$x_2 - x_1=3 - 15.3=- 12.3$ and $y_2 - y_1=-14 - 6=-20$.

Step3: Square the differences

$(x_2 - x_1)^2=(-12.3)^2 = 151.29$ and $(y_2 - y_1)^2=(-20)^2 = 400$.

Step4: Sum the squared differences

$151.29+400 = 551.29$.

Step5: Calculate the square - root

$d=\sqrt{551.29}\approx23.5$.

Answer:

$23.5$