Question

find the distance between the two points in simplest radical form. (8, 6) and (3, -6)
answer attempt 1 out of 2

Explanation:

Step1: Recall distance formula

The distance $d$ between points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step2: Assign coordinates

Let $(x_1,y_1)=(8,6)$ and $(x_2,y_2)=(3,-6)$

Step3: Compute coordinate differences

$x_2-x_1=3-8=-5$, $y_2-y_1=-6-6=-12$

Step4: Square the differences

$(-5)^2=25$, $(-12)^2=144$

Step5: Sum and take square root

$d=\sqrt{25+144}=\sqrt{169}=13$

Answer:

13