Question

find the exact value of sin x in simplest form.
triangle with right angle at w, wv = √10, wx = √6, xv = 4

Explanation:

Step1: Recall sine definition

In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify sides for $\angle X$

For $\angle X$, opposite side is $WV = \sqrt{10}$, hypotenuse is $XV = 4$.

Step3: Compute $\sin X$

$\sin X = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{\sqrt{10}}{4}$

Answer:

$\frac{\sqrt{10}}{4}$