Question

find the following product and write the result in standard form, a + bi.\\((-8 + i)(-8 - i)\\)\\((-8 + i)(-8 - i) = \square\\)

Explanation:

Step1: Apply FOIL method

$(-8)(-8) + (-8)(-i) + i(-8) + i(-i)$

Step2: Calculate each term

$64 + 8i - 8i - i^2$

Step3: Substitute $i^2=-1$

$64 + 8i - 8i - (-1)$

Step4: Simplify the expression

$64 + 1 + (8i - 8i) = 65 + 0i$

Answer:

$65$