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Question
find the inverse of h(x). then graph the inverse.
- h(x)=3x^3
Step1: Replace $h(x)$ with $y$
$y = 3x^{3}$
Step2: Swap $x$ and $y$
$x = 3y^{3}$
Step3: Solve for $y$
First, divide both sides by 3: $\frac{x}{3}=y^{3}$. Then take the cube - root of both sides: $y=\sqrt[3]{\frac{x}{3}}$. So, $h^{-1}(x)=\sqrt[3]{\frac{x}{3}}$.
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$h^{-1}(x)=\sqrt[3]{\frac{x}{3}}$