Question

find the limit. lim(x→0) (x^3 - 6x + 8)/(x - 2) 0 -4 does not exist 4

Explanation:

Step1: Substitute x = 0

Substitute \(x = 0\) into \(\frac{x^{3}-6x + 8}{x - 2}\).
\(\frac{0^{3}-6\times0 + 8}{0 - 2}\)

Step2: Simplify the expression

Calculate the numerator \(0^{3}-6\times0 + 8=8\) and denominator \(0 - 2=-2\). Then \(\frac{8}{-2}=-4\).

Answer:

-4