Question

find the midpoint of the line segment with endpoints $left(-\frac{3}{2},\frac{1}{2}
ight)$ and $left(-\frac{17}{2},-\frac{9}{2}
ight)$. the midpoint of the line segment is $square$. (type an ordered pair, using integers or fractions.)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-\frac{3}{2}$, $y_1=\frac{1}{2}$, $x_2 =-\frac{17}{2}$, $y_2=-\frac{9}{2}$.

Step2: Calculate the x - coordinate of the mid - point

$x=\frac{-\frac{3}{2}+(-\frac{17}{2})}{2}=\frac{-\frac{3 + 17}{2}}{2}=\frac{-\frac{20}{2}}{2}=\frac{- 10}{2}=-5$.

Step3: Calculate the y - coordinate of the mid - point

$y=\frac{\frac{1}{2}+(-\frac{9}{2})}{2}=\frac{\frac{1-9}{2}}{2}=\frac{\frac{-8}{2}}{2}=\frac{-4}{2}=-2$.

Answer:

$(-5,-2)$