Question

find the numbers. find 2 numbers such that 3 times the first minus twice the second is 25 and the second is one more than the first.

Explanation:

Step1: Let the first number be $x$ and the second number be $y$.

Set up equations based on the problem. Given that $y=x + 1$ and $3x-2y=25$.

Step2: Substitute $y=x + 1$ into $3x-2y=25$.

$3x-2(x + 1)=25$.

Step3: Expand the left - hand side.

$3x-2x-2=25$.

Step4: Simplify the left - hand side.

$x-2=25$.

Step5: Solve for $x$.

Add 2 to both sides: $x=25 + 2=27$.

Step6: Solve for $y$.

Since $y=x + 1$, then $y=27+1=28$.

Answer:

The first number is 27 and the second number is 28.