Question

find the perimeter of the rectangle below.
a b
d c
$sqrt{27}$
$2sqrt{3}$
$10sqrt{3}$
$6sqrt{3}$
$8sqrt{3}$
$12sqrt{3}$

Explanation:

Step1: Simplify side - lengths

Simplify $\sqrt{27}=\sqrt{9\times3}=3\sqrt{3}$.

Step2: Recall perimeter formula

The perimeter formula for a rectangle is $P = 2(l + w)$, where $l$ and $w$ are the length and width. Here $l = 3\sqrt{3}$ and $w=2\sqrt{3}$.

Step3: Calculate perimeter

$P = 2(3\sqrt{3}+2\sqrt{3})=2\times5\sqrt{3}=10\sqrt{3}$.

Answer:

A. $10\sqrt{3}$