Question

find the product.$(a^{2})(2a^{3})(a^{2}-8a+9)LXB0\bigcirc$ $2a^{7}-16a^{6}-18a^{5}LXB1\bigcirc$ $2a^{12}-16a^{7}+18a^{6}$done

Explanation:

Step1: Multiply first two terms

$(a^2)(2a^3) = 2a^{2+3} = 2a^5$

Step2: Distribute $2a^5$ to trinomial

$2a^5(a^2 - 8a + 9) = 2a^5 \cdot a^2 - 2a^5 \cdot 8a + 2a^5 \cdot 9$

Step3: Simplify each term

$2a^{5+2} - 16a^{5+1} + 18a^5 = 2a^7 - 16a^6 + 18a^5$

Answer:

A. $2a^7 - 16a^6 + 18a^5$