Question

find the product.
$5a^{2}\left(4a^{2}+3a-4\
ight)$

Explanation:

Step1: Distribute the term outside

Multiply $5a^2$ by each term inside the parentheses.

Step2: Multiply with first term

$5a^2 \times 4a^2 = 20a^{2+2} = 20a^4$

Step3: Multiply with second term

$5a^2 \times 3a = 15a^{2+1} = 15a^3$

Step4: Multiply with third term

$5a^2 \times (-4) = -20a^2$

Step5: Combine all results

Add the products from Steps 2-3-4.

Answer:

$20a^4 + 15a^3 - 20a^2$