Question

find the product of the following factors:
$2(x - 1)(x + 3)$
product: $square x^2 + square x + square$

Explanation:

Step1: Multiply (x - 1)(x + 3)

Using the distributive property (FOIL method):
$(x - 1)(x + 3) = x \cdot x + x \cdot 3 - 1 \cdot x - 1 \cdot 3 = x^2 + 3x - x - 3 = x^2 + 2x - 3$

Step2: Multiply by 2

Multiply the result from Step 1 by 2:
$2(x^2 + 2x - 3) = 2x^2 + 4x - 6$

Answer:

For the $x^2$ term coefficient: $2$
For the $x$ term coefficient: $4$
For the constant term: $-6$

So the product is $2x^2 + 4x - 6$, with the coefficients (or constant) being $2$, $4$, and $-6$ for the respective boxes.