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Question
find pythagorean triples
pythagorean triples are sets of three positive, whole numbers that represent the lengths of the sides of a right triangle.
they satisfy the equation $a^2 + b^2 = c^2$, where $a$, $b$, and $c$ are side lengths, with $c$ being the longest side. explore
pythagorean triples by completing each question in this activity.
question 1
determine if each set of numbers represents a pythagorean triple.
select the correct text in the table.
| $a$ | $b$ | $c$ | pythagorean triple? |
|---|---|---|---|
| 12 | 35 | $20\sqrt{3}$ | yes no |
| 5 | 10 | $5\sqrt{5}$ | yes no |
| 8 | 12 | 15 | yes no |
| 20 | 99 | 101 | yes no |
Step1: Check first set (5,12,13)
Calculate $a^2 + b^2$ and $c^2$:
$5^2 + 12^2 = 25 + 144 = 169$
$13^2 = 169$
Since $5^2 + 12^2 = 13^2$, all are whole numbers.
Step2: Check second set (12,35,$20\sqrt{3}$)
$20\sqrt{3}$ is not a whole number, so it fails the definition.
Step3: Check third set (5,10,$5\sqrt{5}$)
$5\sqrt{5}$ is not a whole number, so it fails the definition.
Step4: Check fourth set (8,12,15)
Calculate $a^2 + b^2$ and $c^2$:
$8^2 + 12^2 = 64 + 144 = 208$
$15^2 = 225$
Since $208
eq 225$, it is not a triple.
Step5: Check fifth set (20,99,101)
Calculate $a^2 + b^2$ and $c^2$:
$20^2 + 99^2 = 400 + 9801 = 10201$
$101^2 = 10201$
Since $20^2 + 99^2 = 101^2$, all are whole numbers.
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| a | b | c | Pythagorean triple? |
|---|---|---|---|
| 12 | 35 | $20\sqrt{3}$ | No |
| 5 | 10 | $5\sqrt{5}$ | No |
| 8 | 12 | 15 | No |
| 20 | 99 | 101 | Yes |