Question

find the sum:
\\(\frac{x - 2}{x^2 + 1} + \frac{x + 3}{x^2 + 1}\\)
\\(\boldsymbol{\frac{2x + 1}{2x^2 + 2}}\\)
\\(\frac{1}{x^2 + 1}\\)
\\(\frac{2x + 1}{x^2 + 1}\\)
\\(\frac{2}{x}\\)

Explanation:

Step1: Combine numerators (common denominator)

$\frac{(x-2)+(x+3)}{x^2+1}$

Step2: Simplify the numerator

$\frac{x-2+x+3}{x^2+1} = \frac{2x+1}{x^2+1}$

Answer:

C. $\frac{2x+1}{x^2+1}$