Question

find the sum or difference.
$-isqrt{3} - 4 - (4 - 6isqrt{3}) - (2 - isqrt{3})$
$-isqrt{3} - 4 - (4 - 6isqrt{3}) - (2 - isqrt{3}) = square$
(simplify your answer. type your answer in the form $a + bi$. typ

Explanation:

Step1: Remove parentheses

First, we distribute the negative signs to the terms inside the parentheses.
\[

$$\begin{align*} &-i\sqrt{3}-4-(4 - 6i\sqrt{3})-(2 - i\sqrt{3})\\ =&-i\sqrt{3}-4 - 4+6i\sqrt{3}-2 + i\sqrt{3} \end{align*}$$

\]

Step2: Combine real parts and imaginary parts separately

For the real parts: \(-4-4 - 2=-10\)
For the imaginary parts: \(-i\sqrt{3}+6i\sqrt{3}+i\sqrt{3}=6i\sqrt{3}\)

Step3: Combine the results

Now we combine the real and imaginary parts to get the final result in the form \(a + bi\).
\[
-10+6\sqrt{3}i
\]

Answer:

\(-10 + 6\sqrt{3}i\)