Question

find two consecutive whole numbers that $sqrt{21}$ lies between.

Explanation:

Step1: Find perfect - squares around 21

We know that \(4^2=16\) and \(5^2 = 25\).

Step2: Compare square - roots

Since \(16<21<25\), then \(\sqrt{16}<\sqrt{21}<\sqrt{25}\), which simplifies to \(4 < \sqrt{21}<5\).

Answer:

4 and 5