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find the value of x. 33) 131° (x + 17)° 34) 74° (6x + 4)°

Question

find the value of x.
33)
131° (x + 17)°
34)
74° (6x + 4)°

Explanation:

Step1: Use vertical - angle property for 33

Vertical angles are equal. So, $x + 17=131$.

Step2: Solve for x in 33

Subtract 17 from both sides: $x=131 - 17$.
$x = 114$.

Step3: Use exterior - angle property for 34

The exterior - angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, $6x+4=74$.

Step4: Solve for x in 34

Subtract 4 from both sides: $6x=74 - 4$.
$6x = 70$.
Then divide both sides by 6: $x=\frac{70}{6}=\frac{35}{3}\approx11.67$.

Answer:

  1. $x = 114$
  2. $x=\frac{35}{3}$