Question

find the value of c. pythagorean theorem: a^2 + b^2 = c^2 4 m 1 m c = \sqrt{?}

Explanation:

Step1: Identify values of a and b

Let $a = 1$, $b = 4$

Step2: Apply Pythagorean theorem

$c^{2}=a^{2}+b^{2}=1^{2}+4^{2}=1 + 16=17$

Step3: Solve for c

$c=\sqrt{17}$

Answer:

$\sqrt{17}$