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1. find the volume to the nearest tenth v = \\square m^3

Question

  1. find the volume to the nearest tenth

v = \square m^3

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius and \( h \) is the height.

Step2: Identify the values of \( r \) and \( h \)

From the diagram, the radius \( r = 6\space m \) and the height \( h=11\space m \).

Step3: Substitute the values into the formula

Substitute \( r = 6 \) and \( h = 11 \) into the formula:
\( V=\pi\times(6)^{2}\times11 \)
First, calculate \( 6^{2}=36 \). Then, \( V=\pi\times36\times11 \).
\( 36\times11 = 396 \), so \( V = 396\pi \).

Step4: Calculate the numerical value

Using \( \pi\approx3.14159 \), we have \( V\approx396\times3.14159 \).
\( 396\times3.14159 = 396\times3+396\times0.14159=1188 + 396\times0.14159 \)
\( 396\times0.14159\approx396\times0.14 = 55.44 \) and \( 396\times0.00159\approx0.63 \), so \( 396\times0.14159\approx55.44 + 0.63=56.07 \)
Then \( 1188+56.07 = 1244.07 \). Rounding to the nearest tenth, we get \( V\approx1244.1 \) (or using a calculator directly: \( 396\times3.1415926535\approx1244.07069 \), which rounds to \( 1244.1 \) when rounded to the nearest tenth).

Answer:

\( 1244.1 \)