Question

find the zero of the function of x shown below.
$f(x)=\frac{x + 6}{2}+\frac{x - 2}{5}-\frac{33}{10}$
a. {33}
b. {0}
c. $\left\\{\frac{29}{2}\
ight\\}$
d. {1}

Explanation:

Step1: Set f(x) = 0

$\frac{x+6}{2} + \frac{x-2}{5} - \frac{33}{10} = 0$

Step2: Multiply by 10 (LCD)

$10\times\frac{x+6}{2} + 10\times\frac{x-2}{5} - 10\times\frac{33}{10} = 10\times0$
$5(x+6) + 2(x-2) - 33 = 0$

Step3: Expand parentheses

$5x + 30 + 2x - 4 - 33 = 0$

Step4: Combine like terms

$7x - 7 = 0$

Step5: Solve for x

$7x = 7$
$x = \frac{7}{7} = 1$

Answer:

D. {1}