Question

c. the fish and wildlife agency measured the size of pacific salmon for 1 year and recorded the average weight for each species.
salmon species: king, sockeye, silver, chum, humpback
average weight (lbs): 15, 8, 12, 15, 5
d. the national oceanic and atmospheric administration measured the pressure of the atmosphere at various altitudes.
altitude (m): 0, 2750, 5486, 8376
atmos. pressure (atm): 1.000, 0.750, 0.500, 0.333
altitude (m): 16132, 30901, 48467
atmos. pressure (atm): 0.100, 0.010, 0.001

Explanation:

Part c: Average Weight of Salmon Species

Step1: Identify the weights

The weights for each species are: King = 15 lbs, Sockeye = 8 lbs, Silver = 12 lbs, Chum = 15 lbs, Humpback = 5 lbs.

Step2: Sum the weights

Sum = \( 15 + 8 + 12 + 15 + 5 \)
\( = 15+8 = 23 \); \( 23+12 = 35 \); \( 35+15 = 50 \); \( 50+5 = 55 \)

Step3: Calculate the average

Number of species = 5. Average = \( \frac{55}{5} = 11 \)

Answer:

The average weight is 11 lbs.

Part d: (Assuming we need to analyze the pressure - altitude relationship, but since no specific question is given, if we assume finding a pattern or function, but based on the table, let's check the ratio)

Looking at the first table:

• At altitude 0 m, pressure = 1.000 atm
• At 2750 m, pressure = 0.750 atm (ratio \( \frac{0.750}{1.000}=0.75 \), altitude ratio \( \frac{2750}{0}= \) undefined, but maybe exponential? Wait, second table:

Altitude 16132 m, pressure 0.100 atm; 30901 m, 0.010 atm; 48467 m, 0.001 atm. Notice that as altitude increases by a factor (approx 30901/16132 ≈ 1.915, 48467/30901≈1.568), pressure decreases by a factor of 10 each time (0.100→0.010→0.001). The first table: 0→2750→5486→8376. Let's check the pressure ratios: 0.750/1.000 = 0.75; 0.500/0.750≈0.666; 0.333/0.500≈0.666. Maybe a linear or exponential decay. But since the question for part d is not clear, if we assume finding the missing pressure in the first table for altitude 8376 m (already given as 0.333), or maybe the relationship. But since the user's image has part c and d, and part c is solvable as above.

(Note: If the intended question for part d was different, please clarify. For now, part c is solved as above.)