Question

in the following exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function. (f(x)=2(x - 8)^{2}-4). the vertex is (square) (type an ordered pair.)

Explanation:

Step1: Recall vertex - form of parabola

The vertex - form of a parabola is $y = a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola.

Step2: Identify $h$ and $k$ values

For the function $f(x)=2(x - 8)^2-4$, comparing it with $y = a(x - h)^2+k$, we have $h = 8$ and $k=-4$.

Answer:

$(8,-4)$